(5x+1)(4x^2+4x+7)=

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Solution for (5x+1)(4x^2+4x+7)= equation:


Simplifying
(5x + 1)(4x2 + 4x + 7) = 0

Reorder the terms:
(1 + 5x)(4x2 + 4x + 7) = 0

Reorder the terms:
(1 + 5x)(7 + 4x + 4x2) = 0

Multiply (1 + 5x) * (7 + 4x + 4x2)
(1(7 + 4x + 4x2) + 5x * (7 + 4x + 4x2)) = 0
((7 * 1 + 4x * 1 + 4x2 * 1) + 5x * (7 + 4x + 4x2)) = 0
((7 + 4x + 4x2) + 5x * (7 + 4x + 4x2)) = 0
(7 + 4x + 4x2 + (7 * 5x + 4x * 5x + 4x2 * 5x)) = 0
(7 + 4x + 4x2 + (35x + 20x2 + 20x3)) = 0

Reorder the terms:
(7 + 4x + 35x + 4x2 + 20x2 + 20x3) = 0

Combine like terms: 4x + 35x = 39x
(7 + 39x + 4x2 + 20x2 + 20x3) = 0

Combine like terms: 4x2 + 20x2 = 24x2
(7 + 39x + 24x2 + 20x3) = 0

Solving
7 + 39x + 24x2 + 20x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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